Kant Critica Ratiunii Pure Pdf Download

detailed abstract: immanuel kant: critica raiunii pure (kantinomus). marcel chelba. in this paper,. 0 comment e-mail username password comment: internicom offers free internet access, free email and free internet calls. you can use our services from anywhere in the world. all calls are charged as normal calls.q: filter an array based on the value of the property of a different array i'm looking for the most efficient way to filter an array based on the value of a property of a different array. the two arrays in question are as follows: const users = [ id: 1, name: 'john doe' , id: 2, name: 'jane doe' , id: 3, name: 'carol doe' , id: 4, name: 'mark doe' , id: 5, name: 'david doe' , id: 6, name: 'sam doe' , ] const matches = ['1', '3'] i want to filter the users array to return this: [ id: 1, name: 'john doe' , id: 3, name: 'carol doe' , id: 5, name: 'david doe' , id: 6, name: 'sam doe' , ] so far, i have the following, but it doesn't work. const matches = ['1', '3'] const userids = _.map(matches, (id) => users.id) const matchesuserids = _.filter(userids, (userid) => users.id === userid) the reason i've done it this way is because this: const matchesuserids = _.filter(users, (user) => _.includes(matches, user.id)) does not work because the name properties are different. so, i want to filter it down to the userids first, before the name properties are even checked. any ideas? a: you could map the users with an array of the matches and filter the array with array.filter(). var users = [ id: 1, name: 'john doe' , id: 2, name: 'jane doe' , id: 3, name: 'carol doe' , id: 4, name: 'mark doe' , id: 5, name: 'david doe' , id: 6, name: 'sam doe' ], matches = ['1', '3'], result = users.map(( id ) => matches.includes(id)) .filter(([, x]) => x); console.log(result); .